Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 45

Answer

$15\sqrt{3}$

Work Step by Step

Adding all the sides of the trapezoid, the perimeter is \begin{array}{l}\require{cancel} 3\sqrt{3}+2\sqrt{12}+\sqrt{12}+2\sqrt{27} .\end{array} Using the properties of radicals, the expression above simplifies to \begin{array}{l}\require{cancel} 3\sqrt{3}+2\sqrt{4\cdot3}+\sqrt{4\cdot3}+2\sqrt{9\cdot3} \\\\= 3\sqrt{3}+2\sqrt{(2)^2\cdot3}+\sqrt{(2)^2\cdot3}+2\sqrt{(3)^2\cdot3} \\\\= 3\sqrt{3}+2(2)\sqrt{3}+2\sqrt{3}+2(3)\sqrt{3} \\\\= 3\sqrt{3}+4\sqrt{3}+2\sqrt{3}+6\sqrt{3} \\\\= 15\sqrt{3} .\end{array}
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