Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 50

Answer

$9x^2-6x\sqrt{2}+2$

Work Step by Step

Using $(a-b)^2=a^2-2ab+b^2$ or the square of a binomial, then, \begin{array}{l} \left( 3x-\sqrt{2} \right)\left( 3x-\sqrt{2} \right) \\= \left( 3x-\sqrt{2} \right)^2 \\= (3x)^2+2(3x)(-\sqrt{2})+(-\sqrt{2})^2 \\= 9x^2-6x\sqrt{2}+2 .\end{array}
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