Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 33b

Answer

$\dfrac{2x^2+7x-6}{(x+2)(x-2)}$

Work Step by Step

Using the $LCD= (x+2)(x-2) ,$ the given expression, $ \dfrac{3}{x+2}+\dfrac{2x}{x-2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{(x-2)(3)+(x+2)(2x)}{(x+2)(x-2)} \\\\= \dfrac{3x-6+2x^2+4x}{(x+2)(x-2)} \\\\= \dfrac{2x^2+7x-6}{(x+2)(x-2)} .\end{array}
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