Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 20

Answer

$(6,0)$

Work Step by Step

Given Equations, $\frac{x}{6} - \frac{y}{2} = 1$ Equation $(1)$ $\frac{x}{3} - \frac{y}{4} = 2$ Equation $(2)$ Taking LCD, Multiply Equation $(1)$ by $6$ and multiply Equation $(2)$ by $12$ $6(\frac{x}{6} - \frac{y}{2} )= 6(1)$ $x-3y=6$ Equation $(3)$ $12(\frac{x}{3} - \frac{y}{4} ) = 12(2)$ $4x-3y=24$ Equation $(4)$ From Equation $(3)$, $x-3y=6$ $x=3y+6$ Substituting $x$ in Equation $(4)$ $4x-3y=24$ $4(3y+6)-3y=24$ $12y+24-3y=24$ $9y=24-24$ $9y=0$ $y=0$ Substituting $y$ value in Equation $x=3y+6$ we get, $x=3y+6$ $x=3(0)+6$ $x=6$ Solution: $(6,0)$
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