Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 23

Answer

$6.0\times(10^{-5})$

Work Step by Step

Using scientific notation and the laws of exponents, the given expression, $ \dfrac{2000\times0.000021}{700} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{(2.0\times10^3)\times(2.1\times10^{-5})}{7.0\times10^2} \\\\= (2\cdot2.1\div7.0)\times(10^3\cdot10^{-5}\div10^2) \\\\= 0.6\times(10^{3+(-5)-2}) \\\\= 0.6\times(10^{-4}) \\\\= 6.0\times(10^{-5}) .\end{array}
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