Answer
$6y^3+7y^2-6y+1$
Work Step by Step
Using the Distributive Property, the given expression, $
(3y-1)(2y^2+3y-1)
,$ is equivalent to
\begin{array}{l}\require{cancel}
3y(2y^2)+3y(3y)+3y(-1)-1(2y^2)-1(3y)-1(-1)
\\\\=
6y^3+9y^2-3y-2y^2-3y+1
\\\\=
6y^3+(9y^2-2y^2)+(-3y-3y)+1
\\\\=
6y^3+7y^2-6y+1
.\end{array}
