Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 27b

Answer

$10x^3-27x^2+32x-21$

Work Step by Step

Using the Distributive Property, the given expression, $ (2x-3)(5x^2-6x+7) ,$ is equivalent to \begin{array}{l}\require{cancel} 2x(5x^2)+2x(-6x)+2x(7)-3(5x^2)-3(-6x)-3(7) \\\\= 10x^3-12x^2+14x-15x^2+18x-21 \\\\= 10x^3+(-12x^2-15x^2)+(14x+18x)-21 \\\\= 10x^3-27x^2+32x-21 .\end{array}
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