Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 30

Answer

$(x-1)(x^2+4)$

Work Step by Step

Using factoring by grouping, then factored form of the given expression, $ x^3-x^2+4x-4 $ is \begin{array}{l}\require{cancel} (x^3-x^2)+(4x-4) \\\\= x^2(x-1)+4(x-1) \\\\= (x-1)(x^2+4) .\end{array}
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