Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 25a

Answer

$P(1)=-4$

Work Step by Step

Substituting $x$ with $1$ in given function, $ P(x)=3x^2-2x-5 ,$ then \begin{array}{l}\require{cancel} P(1)=3(1)^2-2(1)-5 \\\\ P(1)=3(1)-2(1)-5 \\\\ P(1)=3-2-5 \\\\ P(1)=-4 .\end{array}
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