Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 21c

Answer

$y^{7}$

Work Step by Step

Using $a^m\cdot a^n=a^{m+n},$ the given expression, $ y\cdot y^2\cdot y^4 ,$ simplifies to \begin{array}{l}\require{cancel} y^{1+2+4} \\\\= y^{7} .\end{array}
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