Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 24

Answer

$5.0\times10^{-2}$

Work Step by Step

Using scientific notation and the laws of exponents, the given expression, $ \dfrac{0.0000035\times4000}{0.28} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{(3.5\times10^{-6})\times(4.0\times10^3)}{2.8\times 10^{-1}} \\\\= (3.5\times4.0\div2.8)\times(10^{-6}\cdot10^{3}\div10^{-1}) \\\\= 5.0\times10^{-6+3-(-1)} \\\\= 5.0\times10^{-6+3+1} \\\\= 5.0\times10^{-2} .\end{array}
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