Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 472: 27a

Answer

$2x^2+11x+15$

Work Step by Step

Using the Distributive Property, the given expression, $ (x+3)(2x+5) ,$ is equivalent to \begin{array}{l}\require{cancel} x(2x)+x(5)+3(2x)+3(5) \\\\= 2x^2+5x+6x+15 \\\\= 2x^2+11x+15 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.