Answer
$2x-8$
Work Step by Step
Factoring the expressions and cancelling the common factors between the numerator and the denominator, the given expression, $
(2x^2-6x-8)\div(x+1)
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{2x^2-6x-8}{x+1}
\\\\=
\dfrac{2(x^2-3x-4)}{x+1}
\\\\=
\dfrac{2(x-4)(x+1)}{x+1}
\\\\=
\dfrac{2(x-4)(\cancel{x+1})}{\cancel{x+1}}
\\\\=
2(x-4)
\\\\=
2x-8
.\end{array}
