Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 40

Answer

$9y^2+3y-3+\dfrac{4}{y+\dfrac{2}{3}}$

Work Step by Step

Using the long division below, then \begin{array}{l}\require{cancel}\dfrac{ 9y^3+9y^2-y+2 }{ y+\dfrac{2}{3} }\\\\= 9y^2+3y-3+\dfrac{4}{y+\dfrac{2}{3}} .\end{array}
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