Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set: 10

Answer

$3x+4$

Work Step by Step

Factoring the expressions and cancelling the common factors between the numerator and the denominator, the given expression, $ (3x^2+19x+20)\div(x+5) ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{3x^2+19x+20}{x+5} \\\\= \dfrac{(3x+4)(x+5)}{x+5} \\\\= \dfrac{(3x+4)(\cancel{x+5})}{\cancel{x+5}} \\\\= 3x+4 .\end{array}
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