Answer
$\dfrac{6x^5y+75^4y-24x^3y^2}{3x^4y}= 2x+25 -\dfrac{8y}{x}$
Work Step by Step
Divide the divisor to each term of the dividend to have:
$\\=\dfrac{6x^5y}{3x^4y}+\dfrac{75x^4y}{3x^4y}-\dfrac{24x^3y^2}{3x^4y}
\\\\= 2x+25 -\dfrac{8y}{x}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 6
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