## Intermediate Algebra (6th Edition)

$y+2$
Factoring the expressions and cancelling the common factors between the numerator and the denominator, the given expression, $(y^2+7y+10)\div(y+5) ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{y^2+7y+10}{y+5} \\\\= \dfrac{(y+5)(y+2)}{y+5} \\\\= \dfrac{(\cancel{y+5})(y+2)}{\cancel{y+5}} \\\\= y+2 .\end{array}