Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 52

Answer

$P(-2)=13$

Work Step by Step

Substituting $x$ with $ -2 $ in $ P(x)=x^4-3x^2-2x+5 $, then \begin{array}{l} P(-2)=(-2)^4-3(-2)^2-2(-2)+5 \\\\ P(-2)=(16)-3(4)-2(-2)+5 \\\\ P(-2)=16-12+4+5 \\\\ P(-2)=13 .\end{array}
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