Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 47

Answer

$P(1)=1$

Work Step by Step

Substituting $x$ with $ 1 $ in $ P(x)=x^3+3x^2-7x+4 $, then \begin{array}{l} P(1)=(1)^3+3(1)^2-7(1)+4 \\\\ P(1)=1+3-7+4 \\\\ P(1)=1 .\end{array}
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