Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 3

Answer

$3ab+4$

Work Step by Step

Divide $4a^4b$ to each term of the numerator to have: $\require{cancel} \\=\dfrac{12a^5b^2}{4a^4b} + \dfrac{16a^4b}{4a^4b} \\=\dfrac{\cancel{12a^5b^2}3ab}{\cancel{4a^4b}} + \dfrac{\cancel{16a^4b}4}{\cancel{4a^4b}} \\=3ab+4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.