Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set: 7

Answer

$x+1$

Work Step by Step

Factoring the expressions and cancelling the common factors between the numerator and the denominator, the given expression, $ (x^2+3x+2)\div(x+2) ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x^2+3x+2}{x+2} \\\\= \dfrac{(x+2)(x+1)}{x+2} \\\\= \dfrac{(\cancel{x+2})(x+1)}{\cancel{x+2}} \\\\= x+1 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.