Answer
$(x-1)(x^2+x+1)$
Work Step by Step
The given expression can be written as $x^3-1^3$, which is a difference of two cubes.
RECALL:
A sum or difference of two cubes can be factored using either of the following formulas:
(1) $a^3+b^3=(a-b)(a^2-ab+b^2)$
(2) $a^3-b^3=(a-b)(a^2+ab+b^2)$
Using formula (2) above with $a=x$ and $b=1$ gives:
$x^3-1=(x-1)(x^2+x(1)+1^2) = (x-1)(x^2+x+1)$
