Answer
$2x^2-x$
Work Step by Step
Divide $3x^2$ to each term of the dividend to have:
$\require{cancel}
\\=\dfrac{6x^4}{3x^2} - \dfrac{3x^3}{3x^2}
\\=\dfrac{\cancel{6x^4}2x^2}{\cancel{3x^2}} - \dfrac{\cancel{3x^3}x}{\cancel{3x^2}}
\\=2x^2-x$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 2
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