Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 7 - Functions and Graphs - 7.4 The Algebra of Functions - 7.4 Exercise Set: 9

Answer

$5$

Work Step by Step

RECALL: $(f-g)(x) = f(x) - g(x)$ Using the formula above gives: $(f-g)(x) = (-2x+3)-(x^2-5) \\(f-g)(x)= -2x+3-x^2-(-5) \\(f-g)(x)= -2x+3-x^2+5 \\(f-g)(x)= -x^2-2x+(3+5) \\(f-g)(x)= -x^2-2x+8$ Thus, to evaluate the given expression, substitute 1 to the equation above to obtain: $f(1) -g(1) \\= (f-g)(1) \\= -1^2-2(1)+8 \\=-1-2+8 \\=-3+8 \\=5$
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