Answer
$5$
Work Step by Step
RECALL:
$(f-g)(x) = f(x) - g(x)$
Using the formula above gives:
$(f-g)(x) = (-2x+3)-(x^2-5)
\\(f-g)(x)= -2x+3-x^2-(-5)
\\(f-g)(x)= -2x+3-x^2+5
\\(f-g)(x)= -x^2-2x+(3+5)
\\(f-g)(x)= -x^2-2x+8$
Thus, to evaluate the given expression, substitute 1 to the equation above to obtain:
$f(1) -g(1)
\\= (f-g)(1)
\\= -1^2-2(1)+8
\\=-1-2+8
\\=-3+8
\\=5$