## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{10-3x}{2x^2}$
RECALL: $(f-g)(x) = f(x)-g(x)$ Using the formula above gives: $(r-t)(x) \\= r(x)-t(x) \\=\dfrac{5}{x^2}-\dfrac{3}{2x}$ Make the expressions similar using their LCD $2x^2$ $=\dfrac{5(2)}{x^2(2)}-\dfrac{3(x)}{2x(x)} \\=\dfrac{10}{2x^2}-\dfrac{3x}{2x^2} \\=\dfrac{10-3x}{2x^2}$