Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 7 - Functions and Graphs - 7.4 The Algebra of Functions - 7.4 Exercise Set - Page 476: 7



Work Step by Step

RECALL: $(f+g)(x) = f(x) + g(x)$ Using the formula above gives: $(f+g)(x) = (-2x+3)+(x^2-5) \\(f+g)(x)= x^2-2x+(3-5) \\(f+g)(x)= x^2-2x+(-2) \\(f+g)(x)= x^2-2x-2$ Thus, to evaluate the given expression, substitute 3 to the equation above to obtain: $f(3) +g(3) \\= (f+g)(3) \\= 3^2-2(3)-2 \\=9-6-2 \\=3-2 \\=1$
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