Answer
$(F+F)(1)=-2$
Work Step by Step
RECALL:
$(F+G)(x) = F(x) + G(x)$
Using the formula above gives:
$(F+F)(x)
\\= F(x)+F(x)
\\=(x^2-2)+(x^2-2)
\\=2(x^2-2)
\\=2(x^2)+2(-2)
\\=2x^2-4$
To find $(F+F)(1)$, substitute $1$ to $x$ in the equation above to obtain:
$(F+F)(x) = 2x^2-4
\\(F+F)(1) = 2(1^2)-4
\\(F+F)(1)=2(1)-4
\\(F+F)(1)=2-4
\\(F+F)(1)=-2$
