Answer
$-\dfrac{3}{4}$
Work Step by Step
RECALL:
$(f/g)(x)=\dfrac{f(x)}{g(x)}$
Thus,
$(f/g)(x) = \dfrac{-2x+3}{x^2-5}$
To evaluate the given expression, substitute $3$ to $x$ in the equation above to obtain:
$f(3)/g(3)
\\= (f/g)(3)
\\=\dfrac{-2(3)+3}{3^2-5}
\\=\dfrac{-6+3}{9-5}
\\=\dfrac{-3}{4}
\\=-\dfrac{3}{4}$
