Answer
$5$
Work Step by Step
RECALL:
$(F-G)(x) = F(x) - G(x)$
Using the formula above gives:
$(F-G)(x)
\\= F(x)-G(x)
\\=(x^2-2)-(5-x)
\\=x^2-2-5-(-x)
\\=x^2-7+x
\\=x^2+x-7$
To find $(F-G)(3)$, substitute $3$ to $x$ in the equation above to obtain:
$(F-G)(x) = x^2+x-7
\\(F-G)(3) = 3^2+3-7
\\(F-G)(3)=9+3-7
\\(F-G)(3)=12-7
\\(F-G)(3)=5$
