Answer
$$\frac{x-1}{\left(x-3\right)\left(x^2-9\right)}$$
Work Step by Step
We know the following:
$$ (f\cdot g)(x)=f(x)\cdot g(x)$$
Thus, we find:
$$ \frac{x-1}{x^2-x-6}\cdot \frac{x+2}{x^2-9}\\\frac{x-1}{\left(x-3\right)\left(x^2-9\right)}$$
