Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 7 - Functions and Graphs - 7.4 The Algebra of Functions - 7.4 Exercise Set: 30

Answer

$-\dfrac{1}{6}$

Work Step by Step

RECALL: $(F/G)(x) = \dfrac{F(x)}{G(x)}$ Using the formula above gives: $(F/G)(x) \\= \dfrac{F(x)}{G(x)} \\=\dfrac{x^2-2}{5-x}$ To evaluate the given expression, substitute $-1$ to $x$ in the equation above to obtain: $(F/G)(x) \\=\dfrac{x^2-2}{5-x} \\=\dfrac{(-1)^2-2}{5-(-1)} \\=\dfrac{1-2}{5+1} \\=\dfrac{-1}{6} \\=-\dfrac{1}{6}$
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