Answer
$6$
Work Step by Step
RECALL:
$(f+g)(x) = f(x) + g(x)$
Using the formula above gives:
$(f+g)(x) = (-2x+3)+(x^2-5)
\\(f+g)(x)= x^2-2x+(3-5)
\\(f+g)(x)= x^2-2x+(-2)
\\(f+g)(x)= x^2-2x-2$
Thus, to evaluate the given expression, substitute 4 to the equation above to obtain:
$f(4) +g(4)
\\= (f+g)(4)
\\= 4^2-2(4)-2
\\=16-8-2
\\=8-2
\\=6$
