Answer
$$\frac{2x+7}{\left(x+3\right)\left(x-3\right)\left(x+2\right)}$$
Work Step by Step
We know the following:
$$ (g-f)(x)=g(x)-f(x)$$
Thus, we find:
$$ = \frac{x+2}{x^2-9}-\frac{x-1}{x^2-x-6} \\ \frac{2x+7}{\left(x+3\right)\left(x-3\right)\left(x+2\right)}$$