Answer
$\dfrac{3x}{10}$
Work Step by Step
RECALL:
$(f/g)(x) = \dfrac{f(x)}{g(x)}$
Using the formula above gives:
$(t/r)(x)
\\= \dfrac{t(x)}{r(x)}
\\=\dfrac{\frac{3}{2x}}{\frac{5}{x^2}}$
Use the rule $\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b} \times \dfrac{d}{c}$ to obtain:
$\require{cancel}
\\=\dfrac{3}{2x} \cdot \dfrac{x^2}{5}
\\=\dfrac{3}{\cancel{2x}2} \cdot \dfrac{\cancel{x^2}x}{5}
\\=\dfrac{3x}{10}$
