Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set - Page 344: 85



Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ x^3+5x^2-x-5 ,$ \begin{array}{l} (x^3+5x^2)-(x+5) \\\\= x^2(x+5)-(x+5) \\\\= (x+5)(x^2-1) .\end{array} Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, then the factored form of the expression, $ (x+5)(x^2-1) $, is \begin{array}{l} (x+5)(x+1)(x-1) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.