## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\left( \dfrac{3}{4}+y \right)\left( \dfrac{3}{4}-y \right)$
Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, then the factored form of the given expression, $\dfrac{9}{16}-y^2$, is \begin{array}{l} \left( \dfrac{3}{4}+y \right)\left( \dfrac{3}{4}-y \right) .\end{array}