Answer
$3t(3t+1)(3t-1)$
Work Step by Step
Factoring the $GCF=
3t
$, the given expression, $
27t^3-3t
,$ is equivalent to
\begin{array}{l}
3t(9t^2-1)
.\end{array}
Using $a^2-b^2=(a+b)(a-b)$, the expression above is further factored as
\begin{array}{l}
3t(3t+1)(3t-1)
.\end{array}