## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set: 66

#### Answer

$(mn-8)(mn+4)$

#### Work Step by Step

The two numbers whose product is $ac= 1(-32)=-32$ and whose sum is $b= -4$ are $\{ -8,4 \}$. Using these two numbers to decompose the middle term of the expression, $m^2n^2-4mn-32 ,$ then the factored form is \begin{array}{l} m^2n^2-8mn+4mn-32 \\\\= (m^2n^2-8mn)+(4mn-32) \\\\= mn(mn-8)+4(mn-8) \\\\= (mn-8)(mn+4) .\end{array}

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