Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set: 54

Answer

$3a^2b^2(2b+4a-a^2)$

Work Step by Step

Factoring the $GCF= 3a^2b^2 $, then the given expression, $ 6a^2b^3+12a^3b^2-3a^4b^2 $ is equivalent to \begin{array}{l} 3a^2b^2(2b+4a-a^2) .\end{array}
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