Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set - Page 344: 25



Work Step by Step

Factoring the $GCF= 5x $, then the given expression, $ 5x^5-80x $ is equivalent to \begin{array}{l} 5x(x^4-16) .\end{array} Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, then the complete factored form of the expression above is \begin{array}{l} 5x(x^2+4)(x^2-4) \\\\= 5x(x^2+4)(x+2)(x-2) .\end{array}
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