## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set - Page 344: 75

#### Answer

$\left(6a-\dfrac{5}{4}\right)^2$

#### Work Step by Step

The given expression, $36a^2-15a+\dfrac{25}{16} ,$ is a perfect square trinomial since the first and third terms are both perfect squares and the middle term is twice the product of the square roots of the first and third terms. Hence, the factored form is \begin{array}{l} \left(6a-\dfrac{5}{4}\right)^2 .\end{array}

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