Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set: 40

Answer

$(n+2)(n+p)$

Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ n^2+2n+np+2p ,$ \begin{array}{l} (n^2+2n)+(np+2p) \\\\= n(n+2)+p(n+2) \\\\= (n+2)(n+p) .\end{array}
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