## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$2(4t^2+9y^2)(2t+3y)(2t-3y)$
Factoring the $GCF= 2$, then the given expression, $32t^4-162y^4$ is equivalent to \begin{array}{l} 2(16t^4-81y^4) .\end{array} Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, then the complete factored form of the expression above is \begin{array}{l} 2(4t^2+9y^2)(4t^2-9y^2) \\\\= 2(4t^2+9y^2)(2t+3y)(2t-3y) .\end{array}