Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.6 Factoring: A General Strategy - 5.6 Exercise Set: 42

Answer

$2(4t^2+9y^2)(2t+3y)(2t-3y)$

Work Step by Step

Factoring the $GCF= 2 $, then the given expression, $ 32t^4-162y^4 $ is equivalent to \begin{array}{l} 2(16t^4-81y^4) .\end{array} Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, then the complete factored form of the expression above is \begin{array}{l} 2(4t^2+9y^2)(4t^2-9y^2) \\\\= 2(4t^2+9y^2)(2t+3y)(2t-3y) .\end{array}
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