Answer
$(t^2+3)(t^2-3)$
Work Step by Step
Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, then the factored form of the given expression, $
t^4-9
$, is
\begin{array}{l}
(t^2+3)(t^2-3)
.\end{array}
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