Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 98



Work Step by Step

Using the properties of equality, the value of $x$ in the given equation, $ c\cdot\dfrac{21}{a}=\dfrac{7cx}{2a} $, is \begin{array}{l}\require{cancel} \dfrac{2a}{7c}\cdot\dfrac{21c}{a}=\dfrac{7cx}{2a}\cdot\dfrac{2a}{7c} \\\\ \dfrac{2\cancel{a}}{\cancel{7c}}\cdot\dfrac{\cancel{7c}\cdot3}{\cancel{a}}=\dfrac{14acx}{14ac} \\\\ 6=x \\\\ x=6 .\end{array}
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