## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x=36$
Multiplying both sides by $\dfrac{4}{3}$, then the solution to the given equation, $\dfrac{3}{4}x=27$, is \begin{array}{l}\require{cancel} \dfrac{4}{3}\cdot\dfrac{3}{4}x=27\cdot\dfrac{4}{3} \\\\ \dfrac{\cancel{4}}{\cancel{3}}\cdot\dfrac{\cancel{3}}{\cancel{4}}x=\cancel{3}\cdot9\cdot\dfrac{4}{\cancel{3}} \\\\ x=36 .\end{array}