Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 61



Work Step by Step

Multiplying both sides by $ -5 $, then the solution to the given equation, $ \dfrac{1}{9}=\dfrac{z}{-5} $, is \begin{array}{l}\require{cancel} -5\cdot\dfrac{1}{9}=\dfrac{z}{-5}\cdot(-5) \\\\ -\dfrac{5}{9}=\dfrac{-5z}{-5} \\\\ -\dfrac{5}{9}=z \\\\ z=-\dfrac{5}{9} .\end{array}
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