Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 66



Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the properties of equality to solve the given equation, $ \dfrac{5x}{7}=-\dfrac{10}{14} .$ Then do checking of the solution. $\bf{\text{Solution Details:}}$ Using the Multiplication Property of Equality, the given equation is equivalent to \begin{array}{l}\require{cancel} \dfrac{5x}{7}=-\dfrac{10}{14} \\\\ \dfrac{7}{5}\left( \dfrac{5x}{7} \right)=\dfrac{7}{5}\left( -\dfrac{10}{14} \right) \\\\ x=-\dfrac{70}{70} \\\\ x=-1 .\end{array} Substituting the solved value of the variable in the given equation results to \begin{array}{l}\require{cancel} \dfrac{5x}{7}=-\dfrac{10}{14} \\\\ \dfrac{5(-1)}{7}=-\dfrac{10}{14} \\\\ -\dfrac{5}{7}=-\dfrac{\cancel2(5)}{\cancel2(7)} \\\\ -\dfrac{5}{7}=-\dfrac{5}{7} \text{ (TRUE)} .\end{array} Hence, the solution is $ x=-1 .$
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