Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 79



Work Step by Step

Using properties of equality, the solution to the given equation, $ a-\dfrac{1}{6}=-\dfrac{2}{3} $, is \begin{array}{l}\require{cancel} a-\dfrac{1}{6}+\dfrac{1}{6}=-\dfrac{2}{3}+\dfrac{1}{6} \\\\ a=-\dfrac{4}{6}+\dfrac{1}{6} \\\\ a=-\dfrac{3}{6} \\\\ a=-\dfrac{\cancel{3}}{\cancel{3}\cdot2} \\\\ a=-\dfrac{1}{2} .\end{array}
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