Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 77



Work Step by Step

Using properties of equality, the solution to the given equation, $ 48=-\dfrac{3}{8}y $, is \begin{array}{l}\require{cancel} \left( -\dfrac{8}{3} \right)\cdot48=-\dfrac{3}{8}y\cdot\left( -\dfrac{8}{3} \right) \\\\ \left( -\dfrac{8}{\cancel{3}} \right)\cdot\cancel{3}\cdot16=\dfrac{24}{24}y \\\\ -128=y \\\\ y=-128 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.