Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 77

$y=-128$

Using properties of equality, the solution to the given equation, $ 48=-\dfrac{3}{8}y $, is \begin{array}{l}\require{cancel} \left( -\dfrac{8}{3} \right)\cdot48=-\dfrac{3}{8}y\cdot\left( -\dfrac{8}{3} \right) \\\\ \left( -\dfrac{8}{\cancel{3}} \right)\cdot\cancel{3}\cdot16=\dfrac{24}{24}y \\\\ -128=y \\\\ y=-128 .\end{array}